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2 years ago

How to solve right triangles with no sides or angles given.

Mathematics

1 answer:

MrMuchimi2 years ago

8 0

Use The Law of Cosines to calculate the unknown side.

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Atatürk nicin asker olmak istemis

Norma-Jean [14]

Büyük Önder Mustafa Kemal Atatürk, 1881 yılında Selanik'te dünyaya geldi. 1938 yılında ise vefat etti.

Atatürk, Türkiye Cumhuriyeti'nin kurucusudur.

Atatürk, askerliğe başlayacağı yıllarda devletinin zor durumda olduğunu fark etmiştir. Bu sebeple vatan severliği nedeni ile asker olmuştur..

# 1881-1938 endless

4 0

3 years ago

What is the altitude of an equilateral triangle that has sides of length 40 cm?

Rus_ich [418]

Answer:

Step-by-step explanation:

6 0

3 years ago

Helga [31]

Answer is 3*10^2 for 300

8 0

3 years ago

Which of the following sequences is not arithmetic?

Yanka [14]

Answer:

option c

Step-by-step explanation:

c doesnt follow a pattern

3 0

3 years ago

Read 2 more answers

A box holds 8 red and 4 blue beads. Three beads are taken from the box and not replaced. Determine: The probability that all thr

zubka84 [21]

Answer: $\dfrac{14}{55}, \dfrac{13}{55}$

Step-by-step explanation:

Given

There are 8 red and 4 blue beads

Three beads were taken from the box

(i)No of ways of choosing three red beads out of 12 beads is $^8C_3$

Total no of ways $^{12}C_3$

Probability is

$P=\dfrac{^8C_3}{^{12}C_3}=\dfrac{8\times 7\times 6}{12\times 11\times 10}=\dfrac{2\times 7}{11\times 5}\\P=\dfrac{14}{55}$

(ii)atleast two beads refers to minimum two beads

There can be two possibilities (2B,1 R), (3B, 0R)

$\Rightarrow P=\dfrac{^4C_2\times ^8C_1}{^{12}C_3}+\dfrac{^4C_3}{^{12}C_3}\\\\\Rightarrow P=\dfrac{6\times 8}{220}+\dfrac{4}{220}=\dfrac{52}{220}\\\\\Rightarrow P=\dfrac{13}{55}$

6 0

3 years ago