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nignag [31]
3 years ago
8

What are the correct steps for solving the following equation: 5x - = 21

Mathematics
2 answers:
Dima020 [189]3 years ago
6 0

Answer:

x=4.2

Step-by-step explanation:

1. Divide each side by 5

then thats your answer

ololo11 [35]3 years ago
3 0

Answer:

 x = -21/5 = -4.200

Step-by-step explanation:

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A credit card issuer offers an APR of 13.64% and compounds interest daily. which is it most likely to advertise, its APR or its
nirvana33 [79]
To find the effective interest rate the formula is
R=(1+r/k)^(k)-1
R=?
r=nominal Interest rate 0.1364
K=compounded daily 365
Plug in the formula
R=(1+0.1364÷365)^(365)−1
R=0.1461 This the effective interest rate 14.61%
As you can see that the effective interest rate is greater than the nominal interest rate by
0.1461−0.1364=0.0097×100=0.97%

So the answer is a

Hope it helps!
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3 years ago
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What are positivly charged particles in an atoms nucleus called
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Answer:

proton is the word you're looking for.

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Sine, cosine, and tangent are used when looking for a missing side length in the right triangle. True or False
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I’m pretty sure it’s true
5 0
3 years ago
Modeling real life last week you finish level to of a video game and 32 minutes today you finish level 2 in 28 minutes what is t
rusak2 [61]

Answer:

  -12.5%

Step-by-step explanation:

The percentage change in your time can be computed using ...

  pct change = ((new value)/(old value) -1) × 100%

  = (28/32 -1) × 100%

  = (0.875 -1) × 100% = -12.5%

The time to finish level 2 decreased by 12.5%.

6 0
3 years ago
Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco
Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

d=136

The first part of the trip there was lots of traffic, she only averaged 16 mph;

v_1=16

The second part of the trip there was no traffic so she could drive 44 mph;

v_2=44

She traveled for a total of 5 hours;

t=5

let x represent the time in traffic when she traveled at 16 mph

t_1=x

the time the traffic is clear would be;

t_2=t-t_1=5-x

Recall that distance equals speed multiply by time;

d=v_1t_1_{}_{}^{}+v_2t_2

substituting the values;

136=16x+44(5-x)

solving for x;

\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}

So;

\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

7 0
1 year ago
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