The ball will hit the ground at 2 seconds.
Step-by-step explanation:
Given that,
The path of the ball = h(x)=−2x2+1x+6
Here,
x is the time while h is the height of ball.
When the ball will hit the ground, the height will become zero. Therefore,
h(x)=−2x2+1x+6
0 =−2x2+1x+6
or
2x2 -1x - 6 = 0
This is a quadratic equation, hence by applying quadratic equation formula:
here,
a = 2
b = -1
c = -6
Putting these values in formula, we get
x = 2, -3/2
As the time cannot be negative. Therefore, the ball will hit the ground at 2 seconds.
Since both trapezoids are similar, so LMNO is a scaled version of QRST by some magnitude
so we can easily use the concept of ratios to find x
in other words: x÷2=6÷5
so x=6×2÷5=12/5=2.4
x=2.4
The line of the equation perpendicular to y=5 and cuts through (-5,-7) will be given by
m(x-x1)=y-y1
where m=slope.
from y=0x+5, the slope of the perpendicular line m=0,
thus the equation will be:
0(x--5)=y--7
0=y+7
y=-7
The equation is y=-7
Answer:
<h2>x = 3</h2>
Step-by-step explanation:
Answer:
19,14
Step-by-step explanation:
x=5+y
x+ y= 33
we will solve using substitution
(5+y) +y= 33
5+y+y=33
5+2y=33
subtract 5 from both sides
2y=28
y=14
We got y now we will find what x is
for this, we will substitute y's value (14) into the first equation
x=5+(14)
x=19
we got x too
