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2 years ago

14

WRITE Which solid has a greater volume: cone with a base radious of 7 centimeters and a height of 28 centimeters or a pyramid Wi

th base area 154 square centimeters and height of 28 centimeters? Explain your reasoning

1 answer:

Mumz [18]2 years ago

7 0

The pyramid has a greater volume.
The volume of the cone is 1436.7 ( to 5 sf )
The volume of the pyramid is 1437.3 ( to 5 sf )
Both of them is 1440 when rounded off to 3 sf. However , the volume of the pyramid is greater.
( so sorry I can’t explain well but I hope it helps )
The solution is in the picture:) hope you understand better!! Sorry if It’s confusing

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Answer:

1. Commutative Property of Addition

2. Distributive property

Step-by-step explanation:

Given

$Line 1: 4(8+9x)$

$Line 2: 4(9x+8)$

$Line 3: 36x+32$

Required

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The property from Line 1 to 2 depicts $a + b = b + a$ ;

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2 years ago

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

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Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

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$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

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$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

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We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

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$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

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