2 years ago

State if each scenario involves a permutation or a combination. Then find the number of possibilities.

Mathematics

1 answer:

Drupady [299]2 years ago

8 0

The order can be in a few different ways like 213, 321, 132, 312. You get the idea

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Ad libitum [116K]

Answer:

C. $\sqrt{x + 2} - \sqrt{x}$

Step-by-step explanation:

$\frac{2}{ \sqrt{x} + \sqrt{x + 2} } \\ \\ = \frac{2}{ (\sqrt{x} + \sqrt{x + 2}) } \times \frac{(\sqrt{x} - \sqrt{x + 2})}{(\sqrt{x} - \sqrt{x + 2})} \\ \\ = \frac{2( \sqrt{x} - \sqrt{x + 2}) }{ ({ \sqrt{x} )}^{2} - {( \sqrt{x + 2} )}^{2} } \\ \\ = \frac{2( \sqrt{x} - \sqrt{x + 2}) }{ x - {( x + 2)} } \\ \\ = \frac{2( \sqrt{x} - \sqrt{x + 2}) }{ x - x - 2 } \\ \\ = \frac{2( \sqrt{x} - \sqrt{x + 2}) }{ - 2 } \\ \\ = - ( \sqrt{x} - \sqrt{x + 2}) \\ \\ \frac{2}{ \sqrt{x} + \sqrt{x + 2} } = \purple{ \bold{\sqrt{x + 2} - \sqrt{x} }}$

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