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Rzqust [24]
3 years ago
7

The statement "The square of any rational number is rational" can be rewritten formally as "For all rational numbers x, x 2 is r

ational" or as "For all x, if x is rational then x 2 is rational." Rewrite each of the following statements in the two forms "∀ x, " and "∀x, if , then " or in the two forms "∀ x and y, " and "∀x and y, if , then ."
a. The reciprocal of any nonzero fraction is a fraction.
b. The derivative of any polynomial function is a polynomial function.
c. The sum of the angles of any triangle is 180◦.
d. The negative of any irrational number is irrational.
e. The sum of any two even integers is even.
f. The product of any two fractions is a fraction.
Mathematics
1 answer:
____ [38]3 years ago
3 0

Answer:

a.

For all non zero fraction 1(1/x), 1/x is a fraction

For all 1/(1/x), if 1/(1/x) is non zero, 1/x is a fraction

b.

For all polynomial function f(x) = x³ + x² + x - 1, the derivative (dy/dx) is a polynomial function

For all f(x) x³ + x² + x - 1, if f(x) is polynomial, f'(x) is a polynomial function

c.

For all angles x,y,z of a triangle, the sum, x + y + z = 180

For all x,y,z, if x,y and z are the angles of a triangle, x+y+z = 180

d.

For all irrational numbers x, -x is irrational

For all x, if x is irrational then -x irrational.

e.

For two integers, x and y, the sum x+y is an integer

For x,y if x and y are integers, then x + y is an integer

f.

For two fractions, x/y and a/b the product ax/by is a fraction

For x/y and a/b, if x/y and a/b are fractions then ax/by is a fraction

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Graph the parabola 3x^2+6x-24
brilliants [131]
We have the following function:
 F (x) = 3x ^ 2 + 6x-24
 We observe that it is a quadratic equation.
 The graph is therefore a parabola.
 Its cut points are:
 (-4, 0)
 (2, 0)
 Answer:
 
See attached image to see graph of the function

7 0
3 years ago
Phil has $20,000, part of which he invests at 8% interest and the rest at 6%. If the total income from the two investments was $
Salsk061 [2.6K]

Answer: 7000

Step-by-step explanation:

Let the amount invested in 8% account be P1 and the amount invested in 6% account be P2

. If the total amount invested is $20,000 then:

P1+P2=20,000. (Eq. 1)

The interest earned in one year from the 8% account is:

I1=0.08P1

and the interest earned in one year from the 6% account is:

I2=0.06P2

If the total interest earned is $1460, then:

I1+I2=1460

0.08P1+0.06P2=1460

(Eq. 2) From Eq. 1 :

P1=20000−P2

Substituting this into Eq. 2:

0.08 (20000−P2) + 0.06P2 = 1460

1600 − 0.08P2 + 0.06P2 = 1460

0.02P2 = 140

P2 = 140 / 0.02

P2 = 7000

Hence, he invested $7000 at the rate of 6%.

8 0
3 years ago
Can someone please help me with this?
icang [17]
16/4= 4 so the 16+4=20 and 20 is the answer
3 0
2 years ago
Find the measure of x in each figure
uysha [10]

Answer:

x = 20

Step-by-step explanation:

The two angle are a linear pair. Their measures has a sum of 180 deg.

2x + 140 = 180

2x = 40

x = 20

7 0
4 years ago
The equations 2x+7=3 and bx-10=-2 have the same solution for x. Find the value of b.
White raven [17]

Solve both equations for x:

2x+7 = 3

2x = -4

x = -2

Plug x into the equation which contains b:

b(-2) -10 = -2

-2b = 8

b = -4


Answer:

b = -4

x = -2

4 0
4 years ago
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