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Ganezh [65]
2 years ago
12

Need help 7 th grade math from 5 to 7

Mathematics
1 answer:
Oduvanchick [21]2 years ago
8 0

Answer:

5) B=42° F=69° H=64° K=53°

6) Triangle ABC and Triangle JKL

Triangle DEF and Triangle GHI

Step-by-step explanation:

85+53+x=180

×=180-85-53

×=42

repeat for the rest

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Can someone help me please
VashaNatasha [74]

Answer:

TQ = 10\sqrt{2}

Step-by-step explanation:

The diagonal divides the square into 2 right triangles with the diagonal being the hypotenuse.

Using Pythagoras' identity in triangle TPQ

TQ² = PQ² + PT²

TQ² = 10² + 10² = 100 + 100 = 200 ( take square root of both sides )

TQ = \sqrt{200} = \sqrt{100(2)} = \sqrt{100} × \sqrt{2} = 10\sqrt{2}

7 0
3 years ago
What is the equation of the line that is perpendicular to y, =, 1 over 3 x, 4. And contains the point negative 2, negative 5,?.
Anit [1.1K]

The equation of the line is, \rm y = 3x + 1.

Given that,

The equation of the line is,

\rm y = \dfrac{1}{3} x+4\\

And contains the point (-2, -5).

We have to determine,

What is the equation of the line that is perpendicular to the given line?

According to the question,

The equation of the line is,

\rm = \dfrac{1}{3}x + 4\\

On comparing with the standard equation of the line y = mx +c.

The slope of the line m_1 is 1/3.

When two lines are perpendicular the relation between these slopes is,

\rm m_1\times m_1 = {-1}\\\\\dfrac{-1}{3} \times m_2 = -1\\\\-1 \times m_2 = -1 \times 3\\\\-m_2 = -3\\\\m_2 = 3

And line contains the point (-2, -5).

Then,

\rm y = mx +c \\\\-5 = 3 (-2) + c\\\\-5 = -6+c \\\\c = 6-5 \\\\c = 1

Therefore,

The equation of the line that is perpendicular to the given line and contains the point (-2, -5) is,

\rm y = mx +c \\\\y = 3x +1

Hence, The required equation of the line is, \rm y = 3x + 1.

For more details refer to the link given below.

brainly.com/question/14388443

7 0
3 years ago
I don't understand how to solve this please help
I am Lyosha [343]
Area=pi x radius squared so (3.14)(10)squared = 314
3 0
3 years ago
Read 2 more answers
A taxi charges a base fee plus $0.75/km.
Naily [24]

a) The rate of change in this situation is 0.75 dollars/km

b) The equation for the cost of hiring a taxi in terms of length of the

trip is y = 0.75 x + b

c) The initial value represents in this situation is $1.2

Step-by-step explanation:

The given is:

  • A taxi charges a base fee plus $0.75/km.
  • A 10-km trip costs $8.70

∵ A rate of change is a rate that describes how one quantity

  changes in relation to another quantity

∵ The unit cost of a taxi is 0.75 dollars for each 1 kilometer

∴ The rate of change = 0.75 dollars/km

a) The rate of change in this situation is 0.75 dollars/km

Assume that the cost of hiring a taxi is $y for length of a trip x km

and a base fee of $b

∵ The length of the trip = x km

∵ The cost per km = $0.75

∵ The base fee = $b

∵ The cost of hiring a taxi = $y

- Write an equation for the the cost of hiring a taxi

∴ y = 0.75 x + b

b) The equation for the cost of hiring a taxi in terms of length

of the trip is y = 0.75 x + b

∵ The length of the trip is 10 km

∴ x = 10

∵ The cost of the hiring a taxi is $8.70

∴ y = 8.70

- Substitute these values in the equation of part (b)

∵ y = 0.75 x + b

∴ 8.70 = 0.75(10) + b

∴ 8.70 = 7.5 + b

- Subtract 7.5 from both sides

∴ 1.2 = b

∵ b is the base fee

∴ b is the initial value

∴ The initial value = $1.2

c) The initial value represents in this situation is $1.2

Learn more:

You can learn more about word problems in brainly.com/question/3950386

#LearnwithBrainly

3 0
3 years ago
Read 2 more answers
3x +12 =90 what is x
castortr0y [4]

Answer:

x=26

Step-by-step explanation:

3x +12 =90

subtract 12 from each side

3x=78

divide 3 from each side

x=26

3 0
3 years ago
Read 2 more answers
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