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stellarik [79]
3 years ago
12

What is the solution to the nearest tenth to the equation below? 0.3y = -2

Mathematics
1 answer:
Katen [24]3 years ago
7 0

Answer:

y=-6.6

hope this helps

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if a worker is paid $ 8.16 per hour and works 8.5 hours in one week, how much he or she is paidfor that week
AfilCa [17]
$8.16 is the unit rate per hour so just multiply the amount she makes per hour by hours. so there were 8 whole hours. $8.16*8=$65.28. then you have half an hour so $8.16/2=4.08. add. ANSWER: $69.36
3 0
3 years ago
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What is the value of this expression?<br><br> 27+4×(8−4)
nasty-shy [4]

Answer:

43

Step-by-step explanation:

First, you have to find the value inside the parentheses. That would be 8-4, which is 4.

Now, use the rule of Pedmas, or Bedmas, whatever you prefer. That is Parentheses, exponents, multiplication, addition, subtraction. So, now you have the equation:

27 + 4 x 4.

You would multiply before addition, as shown above, so you would get:

27 + 16

which would equal:

43.

6 0
2 years ago
Solve for x+.15x=3.45
blsea [12.9K]
15x=3.45
divide by 15 on both sides
x=3.3478
4 0
2 years ago
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If an arrow is shot upward on Mars with a speed of 52 m/s, its height in meters t seconds later is given by y = 52t − 1.86t2. (R
Lapatulllka [165]

Answer:

A. (I) v = 46.42 m/s; (ii) v = 47.35 m/s; (III) v = 48.09 m/s; (iv) v = 48.26 m/s; (v) v = 58.28 m/s

B. v = 48.28 m/s

Note: the question is missing some values. The full Question is provided below:

If an arrow is shot upward on Mars with a speed of 52 m/s, its height in meters t seconds later is given by y = 52t − 1.86t2. (Round your answers to two decimal places.)

(a) Find the average speed over the given time intervals. (i) [1, 2] m/s (ii) [1, 1.5] m/s (iii) [1, 1.1] m/s (iv) [1, 1.01] m/s (v) [1, 1.001] m/s

(b) Estimate the speed when t = 1. m/s

Step-by-step explanation:

Height, y = 52t - 1.86t²

Velocity = ∆y/∆t = 52 - 1.86 * 2t = 52- 3.72t

A. Average velocity = (v1 + v2)/2

(i) At t = 1, 2

Average velocity = (52 - 3.72*1 + 52 -3.72*2)/2 = 46.42 m/s

(ii) At t = 1,1.5

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.5)/2 = 47.35 m/s

(iii) At t = 1,1.1

Average velocity = (52 - 3.72*1 + 52 -3.72*1.1)/2 = 48.09m/s

(iv) At to = 1, 1.01

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.01)/2 = 48.26 m/s

(iv) At t = (1, 1.001)s

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.001)/2 = 48.28 m/s

B. Speed at t = 1s

Velocity = 52 - 3.72 * 1 = 48.28 m/s

6 0
2 years ago
This is how you do it
WITCHER [35]
Where's the full question
7 0
3 years ago
Read 2 more answers
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