X, x+1, x+2, x+3 - four consecutive integers
The integers are 169, 170, 171 and 172.
Answer:
5
Step-by-step explanation:
First u minus (because of these () ) witch is 3 and 
is a fraction so u do 3× (u see that its not a ÷ sign because its a fraction) witch equals to 5
If s is the side of the square base, the area of the square base is s^2.
The volume of the square base is,
V = (s²) (h)
s² = V/h
s² = 3n³ + 13n² + 16n + 4 / <span>3n + 1
You can do this division by factoring, synthetic division, or by plain division.
Factoring out 3n + 1 from the numerator gives you:
</span>s² = (3n + 1)(n² + 4n + 4) / 3n+1
s² = n² + 4n + 4
Therefore, the area of the square base is <span>n² + 4n + 4.</span>
The properties that apply true are:
1–as it implies the Pythagorean theorem; a^2+b^2=c^2
3–as it implies the basic rules of visualized geometry.
4–as the greater side(hypotenuse) is opposite the right angle.
NOT 2, as the accrue angles ARE complimentary.
If you are working out the diagonal line you need to use Pythagoras Theroum: c² = a²+b²
c² = 7²+12² = 193
√c² = c = √193 = 13.89
The length of the diagonal side is 13.89,
Hope this helps! :)
