Check the picture below.
keeping in mind that the diagonals in a rhombus always meet at right-angles, thus all angles at point O are all right-angles.
now, notice that the AC angle bisector, cuts the angle at A in two equal halves, and if you look at the triangle BOC, there is a 15.5° angle, and a right-angle, and well, you already know what the last one is.
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Answer:
y = 9x^2 -8x +9
Step-by-step explanation:
The given equation has derivative ...
y' = 2ax +b
The requirements on slope give rise to two equations:
2a(1) +b = 10
2a(-1) +b = -26
Adding these equations together gives ...
2b = -16 ⇒ b = -8
Then we have ...
2a -8 = 10
a = (10 +8)/2 = 9
__
The given point lets us find the constant term c.
y = 9x^2 -8x +c
c = y -(9x -8)x = 29 -(9(2) -8)(2) = 29 -20 = 9
The equation of the parabola is ...
y = 9x^2 -8x +9
FIG A : ANGLE OF BAC = 67.38 °
FIG B : LENGTH OF RT = 10.549 cm
FIG C: LENGTH OF AB = 5.282 cm
FIG D: ANGLE OF ACB = 37.303°
Step-by-step explanation:
Fig A:
ABC angle = ( Opposite side) / (Hypotenuse)
Sin Ф = (12) / (13)
Ф = Sin⁻¹ ( 12/13)
Ф = 67.38 °
Fig B:
By the basic property of trigonometry
Tan Ф = (Opposite side) / (Adjacent side)
Tan Ф = (14)/ X
X= 14 / (Tan 53° )
Length of RT = 10.549 cm
Fig C:
By the basic property of trigonometry
Sin Ф = (Opposite side) / (Hypotenuse)
Sin Ф = (X) / 12.5
X = 12.5 
Sin 25°
X= 5.282 cm
Fig D:
From the basic property of Trigonometry
Tan Ф = (Opposite side) / (Adjacent side)
Tan Ф = (8/10.5)
Ф = Tan⁻¹ ( 8/10.5)
Ф = 37.303°
Answer:
He paid $253.09 in interest.
Step-by-step explanation:
To find how much did he pay in interest, we use the simple intrest formula, that is given by:
In which I is the value paid in interest, P is the money borrowed, r is the yearly interest rate and t is the time.
In our problem, we have that:
He borrowed $4,400, so 
At 4.75% yearly. We measure the time in days, so we have to divide this value by 365. So 
.
From December 26, 2019 to February 21, 2021, there are 422 days, so 
.
He paid $253.09 in interest.
Consider this option:
C³₂₇=27!/(3!*24!)=25*13*9=2925 ways to select 3 students.
