Consider the car driving around a circular track. Once started, the driver maintains a speed of 45 m/h. Compare the driver's vel
ocity with his acceleration in this case.
A)The car is accelerating because it is changing direction but the velocity is constant.
B) The car is traveling at a constant rate of speed so it is not accelerating and the velocity does not change.
C) Acceleration is the change in velocity so the car is experiencing a change in velocity and it is accelerating.
D) The car is traveling at a constant rate of speed so it is not accelerating but the velocity changes because the direction the car travels is constantly changing.
A)The car is accelerating because it is changing direction but the velocity is constant.
B) The car is traveling at a constant rate of speed so it is not accelerating and the velocity does not change.
C) Acceleration is the change in velocity so the car is experiencing a change in velocity and it is accelerating.
D) The car is traveling at a constant rate of speed so it is not accelerating but the velocity changes because the direction the car travels is constantly changing.
2 answers:
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Answer:
n the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
Explanation:
Velocity is a vector therefore it has magnitude and direction, a change in either of the two is the consequence of an acceleration on the system.
In the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
= (v₂-v₁)/Δt
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
= v2/R
In the general case, both the module and the address change
a = Ra ( a_{t}^2 + a_{c}^2)