All categories

3 years ago

A 700 kg racecar slowed from 30 m/s to 15 m/s. What was the change in momentum?

1 answer:

8 0

Momentum equation is

change in momentum = mass•initial velocity•final velocity

so....

p=700(15) because your initial is 30, and your final in 15, so you subtract! hope that helped!

You might be interested in

What is the public storm warning signal that carries winds of 30 to 60 km/hr and can cause no damage to very light damage

Shkiper50 [21]

Answer:

I know u need this

Explanation:

You gave me the runaround

I really hate the runaround

You really got me paranoid

I always keep a gun around

You always give me butterflies

When you come around

7 0

3 years ago

An astronaut is planning a trip to a newly-discovered planet. According to 2 points

rodikova [14]

Answer:

The new planet has more gravity

Explanation:

gravity force = G m1 m2 / r^2

decresing r or increasing the planet mass will increase the force

3 0

3 years ago

A 150-newton force, applied to a wooden crate at an angle of 30° above the horizontal, causes the crate to travel at constant ve

koban [17]

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wtjfavyw

4 0

3 years ago

Two one-coulomb point charges are at a distance of 1.67 m from each other. What is the size of the electric force between the tw

pychu [463]

Explanation:

The given data is as follows.

distance (r) = 1.67 m

$q_{1} = q_{2}$ = 1 C

It is known that formula for electric force between two charges is as follows.

F = $\frac{kq_{1} \times q_{2}}{r^{2}}$

Hence, putting the given values into the above formula as follows.

$\frac{9 \times 10^{9} \times 1 \times 1}{(1.67)^{2}}$

= $3.227 \times 10^{9}$

As it is given that mass of Falcon Heavy rocket is 1421. Therefore, weight of 1 Falcon rocket is as follows.

weight of 1 falcon rocket = $142 \times 10^{3} \times 9.8$

Therefore, number of falcon rockets will be calculated as follows.

No. of falcon rockets = $\frac{3.227 \times 10^{9}}{142000 \times 9.8}$

= $2.31897 \times 10^{3}$

= 2318.9 falcons

Thus, we can conclude that force between the two point charges above is equal to the weight of 2318.9 Falcon Heavy rockets.

5 0

3 years ago

A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar

finlep [7]

Answer:

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

$\displaystyle V=k\frac{Q}{r}$

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

$d=\sqrt2 a$

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

$\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}$

$\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m$

The total potential is

$V_t=V_1+V_2+V_3+V_4$

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of $\pm 3\mu\ C$ . Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

$\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}$

$V_1=V_2=50912\ V$

The total potential is

$V_t=50912\ V+50912\ V=1\times 10^5\ V$

$\boxed{V_t=1\times 10^5\ V}$

6 0

3 years ago