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shusha [124]
4 years ago
11

Which of the following terms relate to the meaning of "physical"?

Physics
2 answers:
zubka84 [21]4 years ago
7 0
Body is definitely one of them
lora16 [44]4 years ago
7 0

Answer:

Body and matter

Explanation:

Physical things are those things which have their own color, state and shape. Physical things can be seen from eyes and felt by touch. In the given options natural law is a conceptual thing not physical, emotions are psychological thing,gravity is a force which we can feel but we can not see it, spiritual ia also a thing of belief.

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Calculate the frequency of the wave shown below.
jenyasd209 [6]

\color{skyblue}{ \underline{  \frak { \: option \: ( \: c \: )  =  2 \: hertz   ✓}}}

\:  \:

Given :

  • Wavelength ( λ ) = 2 m

\:  \:

  • Speed = 4 m/s

\:  \:

We, have to find frequency :

\:

  • \large \tt \: Frequency =  \frac{Speed}{Wavelength ( \: λ \: )}

\:  \:

  • \large \tt \: Frequency =  \frac{4}{2}

\:  \:

  • \large \tt \: Frequency = \cancel  \frac{4}{2}

\:  \:

  • \pink{ \boxed{\large \tt \: Frequency =2 \: Hertz ✓}}

\:  \:

Hope Helps!

5 0
2 years ago
An electron (restricted to one dimension) is trapped between two rigid walls 1.40 nm apart. The electron's energy is approximate
Bumek [7]

Answer:

a)    n = 9.9       b)      E₁₀ = 19.25 eV

Explanation:

Solving the Scrodinger equation for the electronegative box we get

         Eₙ = (h² / 8m L²2) n²

where l is the distance L = 1.40 nm = 1.40 10⁻⁹ m and n the quantum number

 In this case En = 19 eV let us reduce to the SI system

          En = 19 eV (1.6 10⁻¹⁹ J / 1 eV) = 30.4 10⁻¹⁹ J

          n = √ (In 8 m L² / h²)

let's calculate

          n = √ (8  9.1 10⁻³¹ (1.4 10⁻⁹)²  30.4 10⁻¹⁹ / (6.63 10⁻³⁴)²

          n = √ (98)            n = 9.9

since n must be an integer, we approximate them to 10

b) We substitute for the calculation of energy

        In = (h² / 8mL2² n²

        In = (6.63 10⁻³⁴) 2 / (8 9.1 10⁻³¹  (1.4 10⁻⁹)² 10²

        E₁₀ = 3.08 10⁻¹⁸ J

we reduce eV

      E₁₀ = 3.08 10⁻¹⁸ j (1ev / 1.6 10⁻¹⁹J)

      E₁₀ = 1.925 101 eV

      E₁₀ = 19.25 eV

the result with significant figures is

        E₁₀ = 19.25 eV

3 0
3 years ago
Organism would make the best index fossil. Answers a , b , c , d please help
aivan3 [116]

Answer: You didn't put what a, b, c, or d is so how is anyone supposed to know what the answer is?

5 0
3 years ago
Read 2 more answers
The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, what should be the focal length an
yuradex [85]

Answer:

The focal length of the appropriate corrective lens is 35.71 cm.

The power of the appropriate corrective lens is 0.028 D.

Explanation:

The expression for the lens formula is as follows;

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

Here, f is the focal length, u is the object distance and v is the image distance.

It is given in the problem that the given lens is corrective lens. Then, it will form an upright and virtual image at the near point of person's eye. The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, the corrective lens is used.

Put v= -71.4 cm and u= 24.0 cm in the above expression.

\frac{1}{f}=\frac{1}{24}+\frac{1}{-71.4}

\frac{1}{f}=0.028

f= 35.71 cm

Therefore, the focal length of the corrective lens is 35.71 cm.

The expression for the power of the lens is as follows;

p=\frac{1}{f}

Here, p is the power of the lens.

Put f= 35.71 cm.

p=\frac{1}{35.71}

p=0.028 D

Therefore, the power of the corrective lens is 0.028 D.

3 0
3 years ago
Tire or false
spayn [35]
1 and 4 are tire.
2 and 3 are not.
8 0
3 years ago
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