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julia-pushkina [17]

3 years ago

10

Angle ACB is an inscribed angle of circle P. What is the measure of angle ACB if arc MAB is equal to 50 degrees?

2 answers:

kupik [55]3 years ago

7 0

Answer:

nfgxxxxazzzzzhff

Step-by-step explanation:

Yakvenalex [24]3 years ago

3 0

∠ACB is an inscribed angle, so

m∠ACB= (1/2)mAB =(1/2)*50=25⁰

m∠ACB= 25⁰

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What is (4a²)³÷8a²? can you please answer in normal number form (not like 3²)

AleksandrR [38]

Answer:

$8a^4$

Step-by-step explanation:

Hello! $(4a^2)^3=4\cdot4\cdot4\cdot a^2\cdot a^2\cdot a^2=64a^6$ because if you multiply numbers with exponents you add the exponents.

Now we've got $\frac{64a^6}{8a^2}=8a^4$ .

Sadly it has to be in exponential form. You can substitute $a$ into the equation if you know a.

3 0

3 years ago

Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1

Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(c) 0.0039

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

$P(x=r)=^nC_rp^rq^{n-r}$

(a) Exactly two will be drunken drivers.

$P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}$

$P(x=2)=66(0.2)^{2}(0.8)^{10}$

$P(x=2)=\approx 0.28347$

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

$P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)$

$P(x=3\text{ or }x=4)=P(x=3)+P(x=4)$

Using binomial we get

$P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}$

$P(x=3\text{ or }x=4)=0.236223+0.132876$

$P(x=3\text{ or }x=4)\approx 0.369099$

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

$P(x\geq 7)=1-P(x$

$P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]$

$P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]$

$P(x\leq 7)=1-[0.9961]$

$P(x\leq 7)=0.0039$

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

$P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)$

$P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315$

$P(x\leq 5)=0.9806$

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0

3 years ago

Can u help answer this

Sergio [31]

Since x = 2
6(2) = 12/4

12/4 = 3

4 0

3 years ago

Read 2 more answers

Anettt [7]

Step-by-step explanation:

it's 22 due to the sum all the 2 smallest sides bigger than the biggest

5 0

2 years ago

The coordinate grid shows the plot of four equations.

Rom4ik [11]

Answer:

Your answer would be A and B

Step-by-step explanation:

Simply look for the coordinates on the graph and look for the name of the lines that intersect there.

5 0

3 years ago