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mojhsa [17]
2 years ago
14

Identify the remainder when x3 - 3x2 - 9x is divided by x - 6.

Mathematics
1 answer:
kiruha [24]2 years ago
8 0

Let p(x) be any polynomial of degree greater than or equal to one and let 'a' be any real number. If a polynomial p(x) is divided by x - a then the remainder is p(a). Hence by the remainder theorem, 0 is the remainder when x3 + 3x2 + 3x + 1 is divided by x + 1.

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swat32

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6 0
3 years ago
I asked before and didn’t get an answer I really don’t understand this thanks.
dmitriy555 [2]
The answer is D, because that is what you should get when you multiply it out.

4x^2 times x^2 = 4x^4 because...

1) multiply the 4 and the one in front of the x on the second term = 4 then

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terms are like...
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3 0
3 years ago
Read 2 more answers
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mamaluj [8]

Answer:

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Step-by-step explanation:

~~~\sqrt{81 d^6}\\\\=\left(81 d^6 \right)^{\tfrac 12}\\\\=\left(81\right)^{\tfrac 12} \cdot \left(d^6 \right)^{\tfrac 12}\\\\=\left(9^2 \right)^{\tfrac 12} \cdot d^{\tfrac 62}\\\\=9d^3

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2 years ago
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