Solve the expression R/2 greater than or equal to 2.5 ty .

Mathematics

1 answer:

Step2247 [10]3 years ago

4 0

Answer:

R ≥ 5

Step-by-step explanation:

$\frac{R}{2}$ ≥ 2.5 To solve, multiply both sides by 2

2 x $\frac{R}{2}$ ≥ 2.5 x 2

R ≥ 5

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$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}$

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$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}$

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Step-by-step explanation:

$\frac{x + 4}{2} = 1 \\ 2 \times \frac{x + 4}{2} = 1 \times 2 \\ x + 4 = 2 \\ x = 2 - 4 \\ x = - 2 \\ \frac{y + 1}{2} = 3 \\ 2 \times \frac{y + 1}{2} = 3 \times 2 \\ y + 1 = 6 \\ y = 6 - 1 \\ y = 5$