Step-by-step explanation:
A
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Let's solve your inequality step-by-step.
<span><span><span>10x</span>+18</span><<span>−2
</span></span>Step 1: Subtract 18 from both sides.
<span><span><span><span>10x</span>+18</span>−18</span><<span><span>−2</span>−18
</span></span><span><span>10x</span><<span>−20
</span></span>Step 2: Divide both sides by 10.
<span><span><span>10x/</span>10</span><<span><span>−20/</span>10
</span></span><span>x<<span>−2
</span></span>Answer:
<span>x<<span>−<span>2</span></span></span>
Answer:did you ever get it?
Step-by-step explanation:
Answer:
x=90 y=45
Step-by-step explanation:
Answer is C
y and 45 are vertical angles
x=90 (right angle)
