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3 years ago

What is the quotient of 4 2/3s÷4 1/5

Mathematics

2 answers:

Helga [31]3 years ago

6 0

Answer:

$4 \frac{9}{10} s$

Step-by-step explanation:

To divide, convert the mixed numbers into improper fractions.

$\frac{14}{12}s$ ÷ $\frac{21}{5}$

To divide, change it to multiplication and use the reciprocal.

$\frac{14}{12}s * \frac{21}{5} \\\\\frac{14*21}{12*5}s \\\\\frac{294}{60}s \\\\ 4\frac{54}{60}s \\\\4 \frac{9}{10} s$

SpyIntel [72]3 years ago

5 0

Is the s suppose to be “s” there?

Use the inverse of the 2 number & multiply.

14 * 5

—— ——-

3 21

70/63

Reduced to 10/9 or 1 1/9

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The population of a certain species of bird in a region after t years can be modeled by the function P(t)= 1620/1+1.15e^-0.042t

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Answer:

Step-by-step explanation:

The function is $\frac{1620}{1+1.15e^{-0.042t}}$

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The population of birds approaches 1620 as t goes towards infinity. So we can say the max population of the species is 1620.

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3 years ago

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irina1246 [14]

Answer:

b) 10

Step-by-step explanation:

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2 years ago

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The perimeter of a patio is 16m what is the area

Darina [25.2K]

Answer:

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3 years ago

Mr. Smith ordered 27 boxes of baseballs. There were 30 baseballs in each box. How many baseballs did Mr. Smith order?

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Step-by-step explanation:

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Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$