Can you pls help me with this question?

Mathematics

1 answer:

8090 [49]1 year ago

4 0

Answer:

heyyyyy so basically the answers would be 8 and 5 on the first and 2nd one Im thinking ...

Step-by-step explanation:

You might be interested in

Ava, Grace, Jayden, and Zoe together stacked a total of 50 brownies on a tray. Ava stacked 0.14 of the brownies, Grace stacked 4

OLEGan [10]

1. Zoe stacked the most brownies. She stacked 27 brownies out of the 50 brownies.

2. 15

3. 43 + 3n ≥ 70, so n ≥ 9

4. D. 58x + 13 + 58y

5. The answer would be ≤4

6. 9.94 + 10.01p ≤ 70, so p ≤ 6

7. C 40 89

8. D. x+(x+5)=77

Hope I helped you! Please consider marking my answer the brainliest :)

4 0

2 years ago

A percent measures a rate

PtichkaEL [24]

Per 1,000 units the last one

6 0

2 years ago

Read 2 more answers

A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got: