1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
xxTIMURxx [149]
3 years ago
8

Two hoses are filling a pool the first hose fills at a rate of x gallons per minute the second hose fills at a rate of 15 gallon

s per minute less than the first hose.
Mathematics
1 answer:
ohaa [14]3 years ago
7 0
The correct answer would be B!
You might be interested in
7 inches converted to feet
Zarrin [17]
<span>0.583333333 feet

If I helped, press "Thanks" button. It will make me happy</span>
5 0
3 years ago
If you start with 85 milligrams of Chromium 51, used to track red blood cells, which
zysi [14]

About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes (m), measured in milligrams, decreases exponentially in time (t), measured in days. The model that represents such decrease is described below:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

  • m_{o} - Initial mass, in milligrams.
  • m(t) - Current mass, in milligrams.
  • \tau - Time constant, in days.

In addition, the time constant is defined in terms of half-life (t_{1/2}), in days:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m_{o} = 85\,mg, t_{1/2} = 27.7\,d and m(t) = 8.5\,mg, then the time required for decaying is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{27.7\,d}{\ln 2}

\tau \approx 39.963\,d

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}

t\approx 92.018\,d

About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

8 0
2 years ago
Find the value of x. (3 points each)
AleksandrR [38]

Answer:

x+431\frac{x}{y} 2

Step-by-step explanation:

7 0
2 years ago
A survey said that 3 out of 5 students enrolled in higher education took at least one online course last fall. Explain your calc
marysya [2.9K]

Answer:

a) 60% probability that student took at least one online course

b) 40% probability that student did not take an online course

c) 12.96% probability that all 4 students selected took online courses.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they took at least one online course last fall, or they did not. The probability of a student taking an online course is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

3 out of 5 students enrolled in higher education took at least one online course last fall.

This means that p = \frac{3}{5} = 0.6

a) If you were to pick at random 1 student enrolled in higher education, what is the probability that student took at least one online course?

This is P(X = 1) when n = 1. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{1,1}.(0.6)^{1}.(0.4)^{0} = 0.6

60% probability that student took at least one online course.

b) If you were to pick at random 1 student enrolled in higher education, what is the probability that student did not take an online course?

This is P(X = 0) when n = 1.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{1,1}.(0.6)^{0}.(0.4)^{1} = 0.4

40% probability that student did not take an online course

c) Now, consider the scenario that you are going to select random select 4 students enrolled in higher education. Find the probability that all 4 students selected took online courses

This is P(X = 4) when n = 4.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.6)^{4}.(0.4)^{0} = 0.1296

12.96% probability that all 4 students selected took online courses.

3 0
3 years ago
What is the slope of the line passing through the points (0, 4) and (−8, −1)?
Alchen [17]

Answer:

The answer is

\frac{5}{8}  \\

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

m =  \frac{ y_2 - y _ 1}{x_ 2 - x_ 1}  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(0, 4) and (−8, −1)

The slope is

m =  \frac{ - 1 - 4}{ - 8 - 0}  =  \frac{ - 5}{ - 8}  =  \frac{5}{8}  \\

We have the final answer as

\frac{5}{8}  \\

Hope this helps you

4 0
3 years ago
Other questions:
  • 2.38+4.89=3+ _ <br><br>changing expressions??
    7·1 answer
  • Mike is making a nut mixture for an upcoming camping trip. He makes the mixture by combining of a cup of cashews and of a cup of
    7·2 answers
  • How are the values of the 4s in 446,218 related ?
    9·1 answer
  • What is 5p to the -7 power/20p to the 2 power simplified
    15·1 answer
  • A rectangle has an area of x^2-11x+30 and the length of x-5. What is the width?
    10·2 answers
  • What is the answer for 7 5\10- 3 1/5
    10·2 answers
  • What fraction is greater 1/4 or 3/8
    12·2 answers
  • Help wanted and needed I’m not good at math
    11·1 answer
  • (5pg)3=125pg. Is wrong or correct
    15·1 answer
  • Dan received 64 dollars for his birthday. He went to a sporting goods store
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!