Recall the ideal gas law:
<em>P V</em> = <em>n R T</em>
where
<em>P</em> = pressure
<em>V</em> = volume
<em>n</em> = number of gas molecules
<em>R</em> = ideal gas constant
<em>T</em> = temperature
If both <em>n</em> and <em>T</em> are fixed, then <em>n R T</em> is a constant quantity, so for two pressure-volume pairs (<em>P</em>₁, <em>V</em>₁) and (<em>P</em>₂, <em>V</em>₂), you have
<em>P</em>₁ <em>V</em>₁ = <em>P</em>₂ <em>V</em>₂
(since both are equal to <em>n R T </em>)
Solve for <em>V</em>₂ :
<em>V</em>₂ = <em>P</em>₁ <em>V</em>₁ / <em>P</em>₂ = (104.66 kPa) (525 mL) / (25 kPa) = 2197.86 mL
Answer:
2,130
Step-by-step explanation:
1. solve for x.

when 

2. place value for X into equation

Maximim profit is 2,130.
Answer:
3.2
Step-by-step explanation:
All you havw to do is put alot of efort
Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So



has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick