Answer:0.178 moles
Explanation: carbon trihydride seems to be an unusual name for the methyl group CH3–
ionic wt 15
moles = 2.67/15 = 0.178
Tropical rainforest...............................
<span>Soln:
•t: in min
•Q(t): quantity of dye in the tank at time t
•r in= 0: rate of dye poured into the tank per min. Since it is fresh water, so it
is zero.
•r out= density of dye×rate of fluid =Q/900×9: rate of dye flowing out.
•Q(0) = 1×900 g: initial amount of dye in the tank.
•{dQ/dt=rin-rout= 0-Q100 Q(0) = 900g•Q(t)=Ce-1/100t
•Q(0) = 900, C= 900, Q(t) = 900e-1/100t
•Q(t) = 0.01·Q(0), Q(0)e-1/100t= 0.01×Q(0),-t100= ln 0.01, t= 460min</span>
Answer:
how many particles are pushing something
Answer:
a) 0.25 g b) 0.01542 g
Explanation:
Half life of Po-218 = 3.04 minutes
initial mass = 1 g
after 3.04 minutes it will remain 0.5 g
after another 3.04 minutes it will remain 0.25 g
After 6 minutes it will remain approx 0.25 g
B) after another 3.04 minutes it will remain 0.125 g
after another 3.04 minutes it will remain 0.0625 g
after another 3.04 minutes it will remain 0.03125 g
after another 3.04 minutes it will remain 0.015625 g
After 18 minutes it will remain approx 0.01542 g