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Zinaida [17]
3 years ago
14

SHOW WORK A dog weighs 15 lbs, what is that weight in oz?

Chemistry
2 answers:
V125BC [204]3 years ago
8 0

Answer:

240 oz

Explanation:

1 ibs= 16 Oz

15 ibs= 15 × 16 = 240 oz

Hatshy [7]3 years ago
5 0
240oz is the answer to the question
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4.00 dm of oxygen at a pressure of 2 atm and 1.00 dm3 nitrogen at a pressure of 1 atm are introduced into a 2.00 dm3 vessel.
podryga [215]

Answer:

A

Explanation:

5 0
3 years ago
An iron ore contains 39% Fe2O3 by mass. What is the maximum mass of iron that can be recovered from 13.2 kg of this ore?
Mars2501 [29]

Answer:

3.6036

Explanation:

0.39 * 13.2 = 5.148

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Fe2O3 = 0.7

6 0
3 years ago
Look at the diagram below.
Kazeer [188]

Answer:

3rd statment

Explanation:

ray 1 and 2 are same vertical line

5 0
3 years ago
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Planting more vegetation will result in __________ erosion. decreased increased the same can't tell
Sonja [21]
Decreased, this is due to the roots of the plants holding the soil together
6 0
3 years ago
How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃? *
densk [106]

Answer:

26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃

Explanation:

To determine the number of moles of O₂ that are needed to react completely with 35.0 mol of FeCl₃, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction),  and rule of three as follows: if 4 moles of FeCl₃ react with 3 moles of O₂, 35 moles of FeCl₃ with how many moles of O₂ will it react?

molesofO_{2} =\frac{35 moles of FeCl_{3}*3 moles of O_{2}  }{4 moles of FeCl_{3}}

moles of O₂= 26.25 ≅ 26.3

<u><em>26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃</em></u>

7 0
3 years ago
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