All categories

3 years ago

PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST

Mathematics

1 answer:

fredd [130]3 years ago

7 0

Answer:

c and d are your answer!

Step-by-step explanation:

Just tested on this!

Trust me!

Have an amazing day!

You might be interested in

6. Dina is moving and he is going to rent a moving van. She will need it for one day. The cost of renting the van $145 for the d

Marat540 [252]

Answer:

403.75

Step-by-step explanation:

we can write the following equation

.75m+145=price

we just need to plug in 345 for m

.75*345+145=price

put this into a calculator and get 403.75

6 0

3 years ago

COMPETE<br> Answer as a dec<br> 2.8+7.22<br> DONE

Vadim26 [7]

Answer:

Hi, there my name is 1frogaroni and I will be helping you out today!

Step-by-step explanation:

The answer to your question is 10.02.

2.8+7.22

=2.8+7.22

=10.02

You must simplify. if this helped I would be happy to get brainliest in order for me to rank up.

Have a great day!

3 0

3 years ago

Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum

lara [203]

Answer:

Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

$\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\$

$\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\ (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\$

$=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3} \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\$

4 0

3 years ago

F(x) = cot x PRE CALC HELP PLS?!

alisha [4.7K]

Check the picture below.

is it even? well, even functions use the y-axis as a mirror, so a pre-image on the right-side, will be a mirror of the image on the left-side, but in this case it isn't so, if you put a mirror right on the y-axis, the left-side will look a bit different.

does it have a zero at x = 0? well, just look at the graph, is the line touching the x-axis at 0? nope.

does it have an asymptote at 0? well, surely you can see it right there.

8 0

4 years ago

Domain of the function

Umnica [9.8K]

F(x) = ln (6-x); find the domain.

The domain of the "ln" function is (0, infinity), or "x is greater than zero."

Thus, the domain of the given function is "(6-x) is greater than zero."

Solve this: 6-x > 0. Add x to both sides. Then 6 > x, or x < 6 (answer)

6 0

3 years ago

PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST​

PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST