Let;
A(-8,6) B(6,6) C(6, -4) D(-8, -4)
Let's find the length AB
x₁= -8 y₁=6 x₂=6 y₂=6
We will use the distance formula;
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
![=\sqrt[]{(6+8)^2+(6-6)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%286%2B8%29%5E2%2B%286-6%29%5E2%7D)
![=\sqrt[]{14^2+0}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B14%5E2%2B0%7D)

Next, we will find the width BC
B(6,6) C(6, -4)
x₁= 6 y₁=6 x₂=6 y₂=-4
substitute into the distance formula;
![d=\sqrt[]{(6-6)^2+(-4-6)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%286-6%29%5E2%2B%28-4-6%29%5E2%7D)
![=\sqrt[]{(-10)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%28-10%29%5E2%7D)
![=\sqrt[]{100}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B100%7D)

Area = l x w
= 14 x 10
= 140 square units
I'm sorry, but there is not enough information for me to correctly answer this question, please provide more information.
Answer:
Option D) $275
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = $235
Standard Deviation, σ = $20
We are given that the distribution of amount of money spent by students is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.975
Calculation the value from standard normal z table, we have,

Approximately 97.5% of the students spent below $275 on textbook.
l o l
o k
s o
5x=x-9 and 4x-10y=8
lets graph that on desmos cause I'm too lazy to subsitute it .
it has one answer
Answer:
A. 10 animals seen in 1 hour
C. 60 animals seen in 6 hours
i dont know B sorry
Step-by-step explanation: