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3 years ago

In which quadrant angle k lies, if tan k<0, an csc k >

Mathematics

1 answer:

Zanzabum3 years ago

7 0

Answer:

A. QII.

Step-by-step explanation:

The tan < 0 in Quadrants 2 and 3.

The csc > 0 in Quadrants 1 and 2.

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a zoo charges an admission price of $85 for the first 12 members of a group and $6 for each additional member of the group. What

elena-14-01-66 [18.8K]

The largest group that can go to the zoo is 23 members

Step-by-step explanation:

The given is:

A zoo charges an admission price of $85 for the first 12 members of a group and $6 for each additional member of the group
We need to find the largest group that can go to the zoo and spend less than $155 on admission

Assume that the number of members in the group is x

∵ There are x members in the group

∵ The zoo charges an admission price of $85 for the first 12

members of a group and $6 for each additional member

of the group

- Take 12 members from x and multiply the rest members by

6 and then add 85 to the product

∴ The group will spend = 6(x - 12) + 85

∵ The group wants to spend less than 155 to go to the zoo

- use the symbol < between the expression above and 155

∴ 6(x - 12) + 85 < 155

- Simplify the left hand side

∴ 6x - 72 + 85 < 155

- Add like terms in the left hand side

∴ 6x + 13 < 155

- Subtract 13 from both sides

∴ 6x < 142

- Divide both sides by 6

∴ x < 23.67

- Take the largest integer less than 23.67

∵ 23 is the largest integer less than 23.67

∴ The group has 23 members

The largest group that can go to the zoo is 23 members

Learn more:

You can learn more about the inequalities in brainly.com/question/1465430

#LearnwithBrainly

6 0

3 years ago

Write 1.19 as a mixed number

zysi [14]

1 19/100 is your answer........

7 0

3 years ago

Read 2 more answers

Write 8 1/5 as a fraction

marishachu [46]

Answer:

8.2

Step-by-step explanation:

let me know if its wrong

3 0

3 years ago

PLZ HELP I AM STUCK!

zaharov [31]

Every whole number is a rational number: for example, 3=31. ... Everywhole number n can be written as a fraction of integers: n=n1. We aren't required to write it that way; we just need to know that it is possible to express every whole number as a fraction of integers, and hence it is rational.

So I Believe the Correct Answer would Be D) If a number is not a rational number, then it is not a whole number. The converse is true

3 0

4 years ago

Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su

Alja [10]

Answer:

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

Step by step explanation:

$\frac{ {(4 {n}^{4} {q}^{5})}^{2} {(8 {n}^{4} q)}^{-2} }{ {(- 3 {nq}^{9})}^{ - 1} {(4 {n}^{3} {q}^{9}) }^{3} }$

first we will change the terms with negative superscrips to the other side of the fraction

$\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }$

then we will distribute the superscripts

$\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2} {q}^{2} }$

$\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8} {q}^{2} }$

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

${4}^{2 - 3} {q}^{10 + 9 - 2 - 27} {n}^{8 + 1 - 8 - 9} {8}^{ - 2} { (- 3)}^{1}$

${4}^{ - 1} {q}^{ - 10} {n}^{ - 8} {8}^{ - 2} { (- 3)}^{1}$

then we will change again the terms with negative superscrips to the other side of the fraction

$\frac{ - 3}{ 4 \times {8}^{2} {q}^{10} {n}^{8} }$

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

4 0

3 years ago