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3 years ago

For brainiest:):):):):):):)

Mathematics

1 answer:

exis [7]3 years ago

6 0

I used 3.14 for pi to solve easier.

6. 6.28

7. 21.98

8. 94.2

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A flower shop makes 5 bouquets with 18 flowers in each bouquet. They make 7 bouquets with 12 flowers in each bouquet.

Anettt [7]

Answer:

174

Step-by-step explanation:

thanks for the help guys

7 0

2 years ago

How do I simplify the expression around the perimeter of the triangle?

Softa [21]

Answer:

it is either positve 13 or negative 13

Step-by-step explanation:

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3 years ago

Consider the following functions. f1(x) = x, f2(x) = x2, f3(x) = 2x − 4x2 g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, a

bekas [8.4K]

9514 1404 393

Answer:

(c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
NOT linearly independent

Step-by-step explanation:

We want ...

c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0

Substituting for the fn function values, we have ...

c1·x +c2·x² +c3·(2x -4x²) ≡ 0

This resolves to two equations:

x(c1 +2c3) = 0

x²(c2 -4c3) = 0

These have an infinite set of solutions:

c1 = -2c3

c2 = 4c3

Then for any parameter t, including the "trivial" t=0, ...

(c1, c2, c3) = (-2t, 4t, t)

f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)

7 0

2 years ago

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

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3 years ago

which of these is an example of a discrete random variable? A. Time worked on a job B. Weight of a child C. First digit of a pho

sergiy2304 [10]

es la c

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3 years ago

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