Question

Math class, last chance to take it!

Answer 1

Answer:

$\sf x=-4$  $\sf \ and$  $\sf y=45$

Step-by-step explanation:

given:

$\sf{-\frac{1}{2} x+\frac{1}{5} y=11}$

$\sf{3 x+\frac{1}{4} y=-\frac{3}{4} }$

make x subject:

$\sf{-\frac{1}{2} x+\frac{1}{5} y=11}$

$\sf{-\frac{1}{2} x =11-\frac{1}{5}y}$

$\sf{- x =22-\frac{2}{5}y}$

$x =-22+\frac{2}{5}y}$

solve using substitution method:

$\sf{3 x+\frac{1}{4} y=-\frac{3}{4} }$

$\sf{3 (-22+\frac{2}{5}y) +\frac{1}{4} y=-\frac{3}{4} }$

$\sf-66 +\frac{6}{5} y+\frac{1}{4} y = -\frac{3}{4}$

$\sf 1.45y = 65.25$

$\sf y=45$

then x will be:

$x =-22+\frac{2}{5}y}$

$x =-22+\frac{2}{5}(45)}$

$\sf x=-4$