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2 years ago

-3x + 1 - 5x i need the answer quick

Mathematics

2 answers:

otez555 [7]2 years ago

8 0

-3x + 1 - 5x

-3x - 5x

-8x + 1

<h3>The answer is -8x + 1.</h3>

Sergeu [11.5K]2 years ago

5 0

Answer:

-8x + 1

Step-by-step explanation:

hope this si correct

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If x is a positive acute angle and cos x = 3/5, find the value of sinx.

Dima020 [189]

X is a positive acute angle. That means x is located in the first quadrant and has positive value in sin, cos, tan.

The formula of trigonometry ratio
cos x = $\dfrac{\text{adjacent}}{\text{hypotenuse}}$
sin x = $\dfrac{\text{opposite}}{\text{hypotenuse}}$

From the formula of cosine
cos x = $\dfrac{3}{5}$
$\dfrac{\text{adjacent}}{\text{hypotenuse}}= \dfrac{3}{5}$
from the formula above, adjacent side is 3 units, and hypotenuse is 5 units

Draw a right triangle to illustrate the location of the sides. See image attached.

To find the ratio of sine, we need to find the length of opposite side using pythagorean theorem
3² + (opposite)² = 5²
9 + (opposite)² = 25
(opposite)² = 25 - 9
(opposite)² = 16
opposite = 4
The length of opposite side is 4 units

Find sin x
sin x = $\dfrac{\text{opposite}}{\text{hypotenuse}}$
sin x = $\dfrac{4}{5}$

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3 years ago

Find the exact value by using a half angle identity.tan 75°

kramer

The trigonometric function is given as

$\tan 75^{\circ}$

Apply the half angle identity to find the value of tan 75 ,

$\tan (\frac{u}{2})=\frac{\sin u}{1+\cos u}$

Here,

$\tan (\frac{150^{\circ}}{2})=\frac{\sin150^{\circ}}{1+cos150^{\circ}}$ $\tan (75^{\circ})=\frac{\frac{1}{2}}{1-\frac{\sqrt[]{3}}{2}}=\frac{\frac{1}{2}}{\frac{2-\sqrt[]{3}}{2}}^{}$ $\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}$

Now rationalize the function.

$\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}\times\frac{2+\sqrt[]{3}}{2+\sqrt[]{3}}=\frac{2+\sqrt[]{3}}{4-3}=\frac{2+\sqrt[]{3}}{1}$

Again simplify the trigonometric function,

$\tan 75^{\circ}=2+1.732=3.732$

Hence the answer is 3.732.

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22.9 is the closest but not exact. It was probably rounded off.

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