The answer to your question is A
Third term = t3 = ar^2 = 444 eq. (1)
Seventh term = t7 = ar^6 = 7104 eq. (2)
By solving (1) and (2) we get,
ar^2 = 444
=> a = 444 / r^2 eq. (3)
And ar^6 = 7104
(444/r^2)r^6 = 7104
444 r^4 = 7104
r^4 = 7104/444
= 16
r2 = 4
r = 2
Substitute r value in (3)
a = 444 / r^2
= 444 / 2^2
= 444 / 4
= 111
Therefore a = 111 and r = 2
Therefore t6 = ar^5
= 111(2)^5
= 111(32)
= 3552.
<span>Therefore the 6th term in the geometric series is 3552.</span>
Answer:
x=65*
Step-by-step explanation:
theres a small rectangle near x and it means that the angle is 90*
and the upper angle is 180
180+90+25+x=360*
x=65*
Answer:
42 / 7 = 6
Step-by-step explanation:
There are 6 rows in the class room.
Answer: you would have 1,060 in a month if that’s what you are asking
Step-by-step explanation:
