First of all let's rearrange the equation for the given line:
4x + 7y + 3 = 0
7y = -4x - 3
y = (-4/7)x - 3/7
Now we know that the gradient of the line is -4/7
The gradients of two perpendicular lines multiply by each other to give -1, ie.
(-4/7)*m = -1
m = -1/(-4/7)
= 7/4, therefor the gradient of the perpendicular line is 7/4
Now we can substitute this and the point (-2, 1) into the equation y - y1 = m(x - x1)
y - 1 = 7/4(x - (-2))
y = 7/4x + 7/2 + 1
y = 7/4x + 9/2
If we look at the given answers then C is correct, since 9/2 = 18/4 and so the equation may also be written as y = 7/4x + 18/4
The answer is C, moderate negative association
Since R is the midmoint of QS that means that QR and RS are equal to each other. So first you need to find x. There are many different ways to set up the equation to solve for x, but I'll show you the easiest one:
QR+QS=RT+QR
(2x-4)+(2x-4)=(8x-43)+(2x-4)
Combine like terms:
4x-8=10x-47
Isolate Variable:
4x-8=10x-47
-4x -4x
6x-47=-8
Isolate Constant:
6x-47=-8
+47 +47
6x=39
Divide:
x=6.5
Check Your Answer:
(Plug in 6.5 as x)
(4(6.5)-8)=(8(6.5)-43)+(2(6.5)-4)
18=18
Answer:
Step-by-step explanation:
<h3>i) simplify the complex fraction</h3>
<h3>ii) simplify the equation using cross multiplication</h3>
<h3>iii) swap the sides of the equation</h3>
<h3>iv) divide both sides of the equation by -6</h3>
<h3>v) simplify the fraction</h3>
