Answer:
Percentage composition of oxygen = 29.69%
Percentage composition of fluorine = 70.37
Explanation:
Given:
Mass of compound = 0.432 grams
Mass of oxygen = 0.128 grams
Find:
Percentage composition of oxygen
Percentage composition of fluorine
Computation:
Percentage composition of oxygen = [0.128/0.432]100
Percentage composition of oxygen = 29.69%
Percentage composition of fluorine = [(0.432 - 0.128)/0.432]100
Percentage composition of fluorine = 70.37
Answer:
D because the grass is eaten by the antelope and the antelope is eaten bu the lion
Answer:
Explanation:
<u>Molecular formula from Glucose:</u>
C₆H₁₂O₆
<u>3 moles of Glucose:</u>
3C₆H₁₂O₆
In 1 mole of Glucose, there are 12 hydrogen atoms.
<u>In 3 moles:</u>
= 12 × 3
= 36 H atoms
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It depends on the mph
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