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Semenov [28]
3 years ago
11

An atom has 9 electrons and 9 protons at the start . If it loses 2 electrons, the net charge on the atom will be ? If the atom i

nstead gains 4 electrons the net charge will be ?
Chemistry
2 answers:
gtnhenbr [62]3 years ago
7 0

Answer : If it loses 2 electrons, the net charge on the atom will be (+2) and If it gains 4 electrons, the net charge on the atom will be (-4).

Explanation :

We are given:

Number of electron in an atom = 9

Number of protons in an atom = 9

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

An ion is formed when an atom looses or gains electron.

When an atom looses electrons, it will form a positive ion known as cation.

When an atom gains electrons, it will form a negative ion known as anion.

According to the question,

When the atom loses 2 electrons then the net charge on the atom will be (+2) because it will form a positive ion by losing electrons.

When the atom gains 4 electrons then the net charge on the atom will be (-4) because it will form a negative ion by gains electrons.

antoniya [11.8K]3 years ago
6 0
Loses 2= +2 charge
gains 4= -2 charge
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How many moles are in 75.0 grams of nitrogen gas, N2?
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<u>Given:</u><u>                                                                                                                       </u>

Mass of Nitrogen (N₂) gas = 75 grams

<u>Finding the number of moles of N₂:</u><u>                                                                     </u>

We know that the molar mass of N₂ is 28 grams/mole

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Number of moles = 75 / 28

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3 years ago
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2 years ago
Determine the percent composition for each of the elements in magnesium nitrate, Mg(NO3)2. Please round to the nearest whole num
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Answer:

% Mg = 16.2 % ≈ 16 %

%N = 18.9 % ≈ 19 %

% O = 64.9 % ≈ 65 %

Explanation:

Step 1: Data given

Molar mass Mg(NO3)2 = 148 g/mol

Molar mass Mg = 24 g/mol

Molar mass N = 14 g/mol

Molar mass O = 16 g/mol

Step 2: Calculate the percent composition

% Mg = (24/148) *100%

% Mg = 16.2 % ≈ 16 %

% N = (2*14 / 148) * 100%

%N = 18.9 % ≈ 19 %

% O = (6*16/148) * 100%

% O = 64.9 % ≈ 65 %

8 0
3 years ago
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