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Semenov [28]
2 years ago
11

An atom has 9 electrons and 9 protons at the start . If it loses 2 electrons, the net charge on the atom will be ? If the atom i

nstead gains 4 electrons the net charge will be ?
Chemistry
2 answers:
gtnhenbr [62]2 years ago
7 0

Answer : If it loses 2 electrons, the net charge on the atom will be (+2) and If it gains 4 electrons, the net charge on the atom will be (-4).

Explanation :

We are given:

Number of electron in an atom = 9

Number of protons in an atom = 9

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

An ion is formed when an atom looses or gains electron.

When an atom looses electrons, it will form a positive ion known as cation.

When an atom gains electrons, it will form a negative ion known as anion.

According to the question,

When the atom loses 2 electrons then the net charge on the atom will be (+2) because it will form a positive ion by losing electrons.

When the atom gains 4 electrons then the net charge on the atom will be (-4) because it will form a negative ion by gains electrons.

antoniya [11.8K]2 years ago
6 0
Loses 2= +2 charge
gains 4= -2 charge
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Answer:

0.51M

Explanation:

Given parameters:

Initial volume of NaBr = 340mL

Initial molarity  = 1.5M

Final volume  = 1000mL

Unknown:

Final molarity = ?

Solution;

This is a dilution problem whereas the concentration of a compound changes from one to another.

In this kind of problem, we must establish that the number of moles still remains the same.

    number of moles initially before diluting = number of moles after dilution

Number of moles  = Molarity x volume

Let us find the number of moles;

          Number of moles  = initial volume x initial molarity

Convert mL to dm³;

                  1000mL  = 1dm³

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Number of moles  = initial volume x initial molarity  = 0.34 x 1.5 = 0.51moles

Now to find the new molarity/concentration;

               Final molarity  = \frac{number of moles}{Volume}    = \frac{0.51}{1}    = 0.51M

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Given the following equation, how many grams of PbCO3 will dissolve when exactly 1.0 L of 1.00 M H+ is added to 6.00 g of PbCO3?
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4 0
2 years ago
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Answer:

<h2>1.9</h2>

Explanation:

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