Ask question

Ask question

All categories

3 years ago

13

Anna has

2 answers:

earnstyle [38]3 years ago

7 0

Answer:

6.3 ft

Step-by-step explanation:

2.4+3.9=6.3

evablogger [386]3 years ago

4 0

Answer:

6.3

Step-by-step explanation:

3.9+2.4=6.3 let me know if you need help :)

You might be interested in

Judy took $30 with her to spend on popcorn and drinks for her and her friend At the movies popcorn was $5 the price of each soda

Sonbull [250]

So 2 popcorn = $5×2= $10
And 2 soda. =$2.50×2=$ 5
Add $10+$5=$15.... Judy spent $15 from $30

Hoping this will help.

6 0

3 years ago

Which equation demonstrates the distributive property?

PIT_PIT [208]

B because distributive property goes like this:
a(b+c)
a(b)+a(c)
That's just an example though

4 0

4 years ago

Read 2 more answers

Zaire spent 55 hours in 2 weeks working on a science project. She worked 32 hours the first week. Write and solve an addition eq

umka21 [38]

Answer:

23

Step-by-step explanation:

55-32=23

5 0

3 years ago

Read 2 more answers

Find the surface area of the prism HURRY HURRY

Assoli18 [71]

Answer:

should be 192

Step-by-step explanation:

4 0

3 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

4 years ago