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Drupady [299]
3 years ago
14

Solve the equation.

Mathematics
1 answer:
PolarNik [594]3 years ago
3 0

Answer:

t = sqrt(595/1289) or t = -sqrt(595/1289)

Step-by-step explanation:

Solve for t:

29/35 = 17/t^2 - 36

29/35 = 17/t^2 - 36 is equivalent to 17/t^2 - 36 = 29/35:

17/t^2 - 36 = 29/35

Bring 17/t^2 - 36 together using the common denominator t^2:

(17 - 36 t^2)/t^2 = 29/35

Cross multiply:

35 (17 - 36 t^2) = 29 t^2

Expand out terms of the left hand side:

595 - 1260 t^2 = 29 t^2

Subtract 29 t^2 + 595 from both sides:

-1289 t^2 = -595

Divide both sides by -1289:

t^2 = 595/1289

Take the square root of both sides:

Answer: t = sqrt(595/1289) or t = -sqrt(595/1289)

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Answer:

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Step-by-step explanation:

For this problem, you use factorials. Factorials are when you multiply every number below it except zero. So like the factorial of 3 or 3! is 3*2*1 is 6.

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
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sergejj [24]

Answer:

(-1, 6)

Step-by-step explanation:

The midpoint of a line segment is effectively the point that lies halfway between two pairs of coordinates on a line. The coordinates we're concerned with here are (-4, 10) and (2, 2). So first think about what is halfway between -4 and 2 (or you can add -4 and 2 then divide by 2) and do the same with 10 and 2. This will give you (-1, 6).

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Svet_ta [14]

Answer:

  92 attendees had activity cards

Step-by-step explanation:

Let x be the number of students with activity cards. Then 130-x is the number without, and the total revenue is ...

  7x +10(130 -x) = 1024

  7x +1300 -10x = 1024 . . . . eliminate parentheses

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92 students with activity cards attended the dance.

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<em>Comment on the solution</em>

Often, you will see such a problem solved using two equations. For example, they might be ...

Let 'a' represent the number with an activity card; 'w' the number without. Then ...

  • a+w = 130 . . . . the total number of students
  • 7a +10w = 1024 . . . . the revenue from ticket sales

The problem statement asks for the value of 'a', so you want to eliminate w from these equations. You can do that using substitution. Using the first equation to write an expression for w, you have ...

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and making the substitution into the second equation gives ...

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This should look a lot like the equation we used above. There, we skipped the extra variable and went straight to the single equation we needed to solve.

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