Question

Factor completely 4x2 16x. 4x(x 4) x(4x 4) 4(x2 4x) Prime.

Answer 1

Answer:

$4x(x+4)$

Step-by-step explanation:

With the expression $4x^{2} +16x$, start by looking to see if you can take out any x-values. As you can see, both $4x^{2}$ and $16x$ have an x to the first power. You can factor that out, leaving you with the expression $x(4x+16)$. Now you look for the largest numerical value that you can take out. Both 4 and 16 are divisible by 4, so you can factor out the number 4, leaving you with the expression $4x(x+4)$.