We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
Some fractions are 6/8, 9/12 and 12/16
All you have to do is multiply a number by the numerator and denominator
Answer:
49.5 square inches
Step-by-step explanation:
We can split the figure into two easier shapes to find the area of; a triangle and a square.
The formula for a triangle is (b*h)1/2. Once we solve we get 24.5 or 24 1/2.
The formula for a square is l*w. Once we solve we get 25.
To find the area of the shaded region, we would add both area and get 49.5 or 49 1/2 square inches.
We know all the side lengths so can use law of cosines. a=90, b=55, and c=50.
2500=8100+3025-2(90)(55)cos(C)
cos(C)=.8712
C=arccos(.8712)=29.4 degrees
