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Art [367]
2 years ago
13

Write as a power of 3

Mathematics
1 answer:
enyata [817]2 years ago
8 0

Answer:

3⁻ⁿ⁺²

Step-by-step explanation:

we need to make both bases the same

9 can be written as 3²

\frac{3 {}^{n} }{3 {}^{2(n - 1)} }

multiply 2(n-1) = 2n - 2

\frac{3 {}^{n} }{3 {}^{2n - 2} }

I'll rewrite as 3ⁿ ÷ 3²ⁿ⁻²

subtract the exponents when dividing numbers with the same base

n - (2n-2) or n - 1(2n-2) imagine the 1 is there

remember that the whole of (2n-2) is being multiplied by -1, so expanding

n - 2n + 2 = -n + 2

final answer: 3⁻ⁿ⁺²

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