Question

100 POINTS PLEASE HELP ME Y'ALL.. THANKS♥

Answer 1

• No of moles of solute(NaCl)=0.250mol
• Mass of solvent (water) in kg=2.05kg

$\\ \rm\Rrightarrow Molality=\dfrac{Moles\:of\:solute}{Mass\:of\: solvent\:in\:kg}$

$\\ \rm\Rrightarrow Molality=0.250/2.05$

$\\ \rm\Rrightarrow Molality=0.1m$

Answer 2

Answer:

m = 0.122 m

Explanation:

Molality(m): A measure of the number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent.

$\mathrm{Molality\:Formula}:\quad \mathrm m = \dfrac{ mole\:of\:solute }{ mass\:of\:solvent\:in\:kg }$

$\mathrm m = \dfrac{ mole}{ kg }$

$\mathrm{Substitute\:the\:numbers\:into\:the\:"Molality\:Formula"}$

$\mathrm m = \dfrac{ 0.250 }{ 2.05 }$

$\mathrm{Divide\:0.250\:by\:2.05\:and\:get\:0.12195122}$

$\mathrm m = {0.12195122}$

$\mathrm{Round\:to\:the\:nearest\:thousandths\:place}$

$\mathrm m = 0.122$