To solve this we assume
that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas
equation which is expressed as PV = nRT. At a constant pressure and number of
moles of the gas the ratio T/V is equal to some constant. At another set of
condition of temperature, the constant is still the same. Calculations are as
follows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 = 308.15 x 7.80 / 698.15
V2 =3.44 L
What grade are you in I’m in 9th ;-;
Answer:
16.499 × 10∧ 21 atoms
Explanation:
Given data:
mass of P2O5= 0.560 g
number of atoms= ?
first of all we will calculate the molar mass of P2O5:
P = 2×31 g/mol = 62 g/mol
O = 5× 16 = 80 g/mol
molar mass of P2O5 = 142 g/mol
Noe we will find the moles of 0.560 g P2O5:
moles = mass / molar mass
moles = 0.560 g/ 142 g/mol
moles = 0.0039 mol
now we will find the atoms present in 0.0039 moles:
0.0039 × 6.02 × 10∧ 23 molecules
2.357 × 10∧ 21 molecules
P2O5 consist of 7 atoms:
2.357 × 10∧ 21 × 7 = 16.499 × 10∧ 21 atoms
<u>Answer:</u> The equation to calculate the mass of remaining isotope is ![[A]=\frac{20}{10^{-0.217t}}](https://tex.z-dn.net/?f=%5BA%5D%3D%5Cfrac%7B20%7D%7B10%5E%7B-0.217t%7D%7D)
<u>Explanation:</u>
The equation used to calculate rate constant from given half life for first order kinetics:
where,
= half life of the reaction = 
Putting values in above equation, we get:
Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = 
t = time taken for decay process
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial amount of the sample = 20 grams
[A] = amount left after decay process = ? grams
Putting values in above equation, we get:
![0.5=\frac{2.303}{t}\log\frac{20}{[A]}](https://tex.z-dn.net/?f=0.5%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B20%7D%7B%5BA%5D%7D)
Hence, the equation to calculate the mass of remaining isotope is
The southern pacific ocean has a similar symmetric pattern to the seafloor ages of the Atlantic ocean. In the Pacific, the seafloor on one side of the youngest crust gets very old but the seafloor on the other side is much younger.
