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EastWind [94]
3 years ago
5

PLEASE HELP!!!

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0

Answer:

the height of the building is 18.6 m

Step-by-step explanation:

using the Pythagorean theorem

a^2+b^2=C^2

a and b are the shorter legs while c is the hypotenuse

a=32, b=?, c=37

32^2+b^2=37^2

square the known numbers ( a and c)

1024+b^2=1369

subtract 1024 from both sides

b^2=345

square root both sides to cancel the square on b

b=18.5741756

Round if needed b=18.6m

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A^2(64a^2-3)/3=27-4a^2/4
frutty [35]
The answer is a = 3/4 = 0.75

First get rid of the paranthesis,
{a}^{2} (64 {a}^{2}  - 3) = 64 {a}^{4} -  3 {a}^{2}
Then set the denominators equal:
\frac{ 256 {a}^{4}  - 12 {a}^{2}}{12}  =  \frac{81 - 12 {a}^{2} }{12}
Then remove the denominators and solve:
256 {a}^{4}  - 12 {a}^{2}  = 81 - 12 {a}^{2}
Eliminate -12a^2 by adding 12a^2 to both sides:
256 {a}^{4}  = 81
Take the fourth root of them or take the square root twice:
\sqrt[4]{256 {a}^{4} }  =  \sqrt[4]{81}   \\  4a = 3
Divide both sides by 4:
a =  \frac{3}{4}  = 0.75
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3 years ago
If f(x)=x-1/3 and g(x)=3x+1, what is (f o g)(x)?
BlackZzzverrR [31]

Answer:

\[3x+\frac{2}{3}\]

Step-by-step explanation:

\[f(x)=x-\frac{1}{3}\]

\[g(x)=3x+1\]

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= \[f(3x+1)=3x+(\frac{3-1}{3})\]

= \[f(3x+1)=3x+(\frac{2}{3})\]

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