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mrs_skeptik [129]
3 years ago
10

Help me understand please​

Mathematics
1 answer:
erastova [34]3 years ago
6 0

Answer:

V=pi x (r)^2 x h

V-volume r-radius h-height

V= pi x (3)^2 x 9

V= pi x 9 x 9

V= pi x 81

V= 254.47 (rounded)

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ILL MARK BRAINLEST IF YOU GIVE ME RIGHT ANSWER!!!! Which of the following is a Pythagorean triple?
user100 [1]

Answer:

C.(5,5,10)

1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 14, 16, 18, ... 5, 10, 13, 15, 17, 20, 26, 29, 30, 34, 35, ... 25, 50, 75, 100, 150, 169, 175, 200, 225, ...

6 0
3 years ago
Consider the question of whether the home team wins more than half of its games in the National Basketball Association. Suppose
spayn [35]

Answer:

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

The home team therefore wins 50% of its games

This means that p = 0.5

Determine the probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Sample of 80 means that n = 80 and, by the Central Limit Theorem:

\mu = p = 0.65

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5*0.5}{80}} = 0.0559

This probability is 1 subtracted by the pvalue of Z when X = 0.65. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.65 - 0.5}{0.0559}

Z = 2.68

Z = 2.68 has a pvalue of 0.9963

1 - 0.9963 = 0.0037

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

7 0
3 years ago
Find the midpoint of the line segment whose endpoints are the given points. (-24.6, 38.1) and (-25.7, -17.7)
CaHeK987 [17]

Answer:

Midpoint is(-25.15,10.2)

Step-by-step explanation:

A line segment refers to line that has two endpoints.

Let (a,b),(c,d) be the endpoints of a line segment.

Midpoint of the line segment is given by (\frac{a+c}{2} ,\frac{b+d}{2})

Take the given points as follows:

(a,b)=(-24.6,38.1)\\(c,d)=(-25.7,-17.7)

Midpoint of a line segment =(\frac{-24.6-25.7}{2},\frac{28.1-17.7}{2})

=(\frac{-50.3}{2} ,\frac{20.4}{2} )\\=(-25.15,10.2)

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Answer:

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3 years ago
Natalie budgets $146 for yoga training. She buys a yoga mat for $10 and spends $9 per day on yoga classes. Which inequality repr
koban [17]
A or C hope that help
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3 years ago
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