Step-by-step explanation:
<em><u>If you are solving for y :</u></em>
<em><u>
</u></em>
y = 6 - 3x
x + y = 62
Since we already know the value of y, we can use substitution to find the value of x.
x + 6 - 3x = 62
<em><u>Subtract 6 from both sides.</u></em>
x - 3x = 56
<em><u>Combine like terms.</u></em>
-2x = 56
<em><u>Divide both sides by -2</u></em>
x = -28
Now that we know the value of x, we can solve for the value of y.
x + y = 62
-28 + y = 62
<em><u>Add 28 to both sides</u></em>
y = 90
The value of y is 90, and the value of x is -28 (this is your answer)
To make sure that these values are correct, we can plug them into the original equations.
y = 6 - 3x
x + y = 62
90 = 6 - 3(-28)
90 = 90 √ this is correct
-28 + 90 = 62
62 = 62 √ this is also correct
Answer: 70.5°
Solution:
Call B, the measure of the angle CBA
cos(B) = adjacent-leg / hypotenuse = 3 / 9 = 1 / 3
=> B = arc cos (1/3) ≈ 70.5°
I will calculate other measures for you, trying to cover the most common ratios: sine, cosine, tangent
1) (segment CA)^2 + (segment BC)^2 = (hypotenuse)^2
=> (segment CA )^2 = (hypotenuse)^2 - (segment BC)^2 = 9^2 - 3^2 = 81 - 9 = 72
=> segment CA = √72 = 6√2
2) sin(B) = opposite-leg / hypotenuse = 6√2 / 9 =2√2 / 3
3) sin(A) = cos(B) = 1/3
4) cos(A) = sin(B) = 2√2 / 3
5) tan(B) = opposite-leg / adjacent-leg = (2√2 / 3 ) / 3 = 2√2 / 9
6) tang(A) = 3 / (2√2 /3) = 9 /( 2√2) = 9√2 / 4
Answer:
84
Step-by-step explanation:
Answer
let me try but i'm not sure
Step-by-step explanation:
Let's assume AC is a straight line and B is on the line and B is between A and C
AB+BC=AC
3x-1+6x=26
9x=27
x=3
