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3 years ago

Anyone who answers gets brainliest:)

Mathematics

2 answers:

Zarrin [17]3 years ago

6 0

Answer:

3/5

Step-by-step explanation:

Natasha_Volkova [10]3 years ago

5 0

Answer:

$\frac{3}{5}$ would be your answer

Step-by-step explanation:

Since you have $\frac{15}{25}$ and the denominator for the answer is 5. You will be dividing 15 and 25 by 5. Making it look like:

15 ÷ 5 = 3

25 ÷ 5 = 5

so your answer will be

$\frac{3}{5}$

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If A=−2x+8 and B=2x−4, find an expression that equals 2A+B in standard form.

kirza4 [7]

Answer: -2x + 12

Step-by-step explanation:

2A + B = 2(-2x + 8) + (2x - 4) = -4x + 16 + 2x - 4 = -2x + 12

5 0

2 years ago

A rectangular filed is 190m by 270m . A rectangular barn is 23 m by 40 m is built in the field .

Anika [276]

Answer: 50,380m

Step-by-step explanation:

190m * 270m = 51,300m

23m * 40m = 920m

Because the barn is in the field, we subtract the barn's area from the field's area, which leaves us with

51,300m - 920m = 50,380m

4 0

3 years ago

from the line y=2x-10 find the equation of the line that is perpendicular to this line and goes through the point (9,-5)

creativ13 [48]

2 is the slope so the slope perpendicular to that is -1/2 (negative reciprocal)
-5=-1/2(9) 9*-1/2=-4.5 and -4.5 - 0.5 = -5 so the equation for the line is y=-1/2x -0.5

5 0

3 years ago

When Meriden made a cake she used a recipe calling for 3/4 cup of sugar. She was planning to make a huge cake for a family get-t

soldi70 [24.7K]

Meriden would need 2 1/4 cups of sugar because 3*3/4=2 1/4

8 0

4 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

4 years ago

Anyone who answers gets brainliest:)​

Anyone who answers gets brainliest:)