Line segment of length k is divided into 3 equal parts.
so first segment is 0-k/3 and third segment is 2/3k-k
so mid-pt of 1st = k/6 and 3rd = 5/6k
so the distance in between = 5/6k-k/6 = 4/6k = 2/3k
Answer:
10.7
Step-by-step explanation:
Present area = 120 * 80 = 9600 ft^2 so the new area will be 9600 + 4400 = 14000
So if increase in length = x we have
(x + 120)(x + 80) = 14,000
x^2 + 200x + 9600 - 14000 = 0
x^2 + 200x - 4400 = 0
x = 20 feet answer
Area of rectangle = 6 x 7 = 42
area of triangle = 1/2(3)(6) = 9
area of figure = 42 + 9 = 51
answer
51 <span>in²</span>