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taurus [48]
2 years ago
11

I need to find the value of x for this diagram

Mathematics
1 answer:
Burka [1]2 years ago
8 0
X is 50.  The lengths of the radii extending out from the center to the chords are the same length, therefore, the chords are the same distance from the center and have the same measure.
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Can 20 degrees 60 degrees and 100 degrees be a triangle
Ivanshal [37]

Answer: Yes

Step-by-step explanation: The area of a triangle equals 180°

100+60+20=180

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Write an equation for the translation of x ^ 2 + y ^ 2 = 25 by 6 units left and 3 units down.
Aliun [14]
The equation would be: (x + 6)^2 + (y + 3)^2 = 25

This equation will produce a circle. If you add the numbers inside the parenthesis to be squared, you can center of the circle. Thus, translating the shape.
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[2/SEC(¶/3)•[lim x→0 x^3+8x+10]^2]/[lim θ→0 sinθ/θ]
Oliga [24]
Assuming the pilcrow is supposed to represent pi:

\frac{\frac{2}{sec(\frac{\pi}{3})}*(\lim_{x \to 0} x^3+8x+10)^2}{ \lim_{\theta \to 0} \frac{sine(\theta)}{\theta}}\\\frac{\frac{2}{\frac{1}{cosine(\frac{\pi}{3})}}*((0)^3+8(0)+10)^2}{\frac{sine((0))}{(0)}}\\\frac{\frac{2}{\frac{1}{\frac{1}{2}}}*(0+0+10)^2}{\frac{0}{0}}\\\frac{\frac{2}{2}*(10)^2}{ \lim_{\theta \to 0} \frac{cosine(\theta)}{1}}\\\frac{100}{cosine((0))}\\\frac{100}{1}\\100

100
4 0
3 years ago
Pls help me with this​
Free_Kalibri [48]

Answer:

\boxed{\sf \frac{15}{22} }

Step-by-step explanation:

The radius of the circle is 7 cm.

The two legs of the triangles are 7cm as well.

Area of a trinagle is ( base × height )/2.

\frac{7 \times 7}{2} =24.5

Multiply the value by 2 since there are two triangles.

24.5 \times 2 = 49

Calculate the area of the circle.

\pi r^2

The radius is given.

\pi (7)^2

Take \pi as \frac{22}{7}

49(\frac{22}{7} )

=154

Subtract the area of the two triangles from the area of the whole circle.

154-49=105

The area of the shaded part is 105 cm². The total area of the shape is 154cm².

\frac{105}{154} =\frac{15}{22}

5 0
3 years ago
A. True
MrRissso [65]
The answer would be false
8 0
3 years ago
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