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3 years ago

How are you today?! Please be honest

Mathematics

2 answers:

dsp733 years ago

4 0

Answer:
im not so good

Step-by-step explanation:

because I’ve been thinking of things lately not things that cheer me up and I’ve been really stressed as well

son4ous [18]3 years ago

3 0

Answer:

I'm okay yk

Step-by-step explanation:

You might be interested in

PLEASE HELP PLEASE WILL GIVE BRAINILIEST 5 STARS AND THANK YOU TO WHOEVER CAN HELP!

Mnenie [13.5K]

Ok so the lines with two triangles are parralel to eachother. The lines with one are parallel to eachother.

The angle of 109° and angle of z° equal eachother. Z=109°

Since 109°, 33° and y° form a triangle, the sum of the angles will equal 180. Add 109 and 33 to get 142. Subtract 142 from 180 to get y°=38°.

Since z=109, this means that the triangle is congruent with the other. Since the congruent triangles are in a rhombus, then the angles are flipped. Thus, angle x =33°.

z=109°
y=38°
x=33°

3 0

4 years ago

Find cos(β) in the triangle.

svetlana [45]

90°+b+b =180

90°+ 2b=180

2b=180-90

2b= 90

2b=90

2 = 2

b=45°

ave tried I don't know if its correct

8 0

2 years ago

Rolando bought a bag of carrots that weighed 4.07 pounds and a bag of potatoes that weighed 2.88 pounds.How many poumds of veget

Tresset [83]

6.95 pounds of vegetables.

4 0

3 years ago

Colby worked three more hours

faust18 [17]

Duruvdidhu you can get my stuff for you today if not I’ll just ask my buddy to come get it

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3 years ago

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home. Give the value of th

astra-53 [7]

Answer:

The value of the standard error for the point estimate is of 0.0392.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home.

This means that $n = 100, p = \frac{81}{100} = 0.81$

Give the value of the standard error for the point estimate.

This is s. So

$s = \sqrt{\frac{0.81*0.19}{100}} = 0.0392$

The value of the standard error for the point estimate is of 0.0392.

7 0

3 years ago