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SVEN [57.7K]
3 years ago
15

Most computer languages include a function that can be used to generate random numbers.In Excel, the RAND function can be used t

o generate random numbers between 0 and 1.If we let x denote a random number generated using RAND, then x is a continuous random variable with the following probability density function.f(x)={10 for 0≤x≤1 elsewhere f(x)={ 10​ for 0≤x≤1 elsewhere ​ a. Graph the probability density function. b. What is the probability of generating a random number between .25 and .75? c. What is the probability of generating a random number with a value less than or equal to .30? d. What is the probability of generating a random number with a value greater than .60? e. Generate 50 random numbers by entering RAND() into 50 cells of an Excel worksheet. f. Compute the mean and standard deviation for the random numbers in part (e).
Mathematics
1 answer:
Artemon [7]3 years ago
8 0

Answer:

Please see the attached file for the complete answer.

Step-by-step explanation:

Download pdf
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During a recent election, 42 of every 100 registered voters in a certain city voted. If there were 158 , 200 registered voters i
Ivanshal [37]
Seeing as there are 1582 sets of 100 people (158200 ÷ 100) multiplying 42 by 1582 should get you the answer. 1582 × 42 = 66444. 66444 people voted in that city.
3 0
3 years ago
HELP!!! 40 points for right answer! i will upvote brainliest!!
krok68 [10]
It is C: Given, Reflexive Property

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3 years ago
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An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.
saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

  • a = 10
  • b = 16
  • c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need b^2 < a^2+c^2 to be true in order for an acute triangle to happen.

So,

b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0
2 years ago
Find the x and y intercepts of the quadratic equation<br> f(x)=-x^2+4x-4
earnstyle [38]
<u>X - Intercept</u>
f(x) = -x² + 4x - 4
   0 = -x² + 4x - 4
   x = <u>-(4) +/- √((4)² - 4(-1)(-4))</u>
                         2(-1)
   x = <u>-4 +/- √(16 - 16)</u>
                    -2
   x = <u>-4 +/- √(0)
</u>               -2<u>
</u>   x = <u>-4 +/- 0
</u>              -2<u>
</u>   x = <u>-4 + 0</u>      x = <u>-4 - 0</u>  
            -2                 -2
   x = <u>-4</u>             x = <u>-4</u>
         -2                   -2
   x = 2               x = 2

The solution to the problem is {2, 2}, or {2}. The x - intercept of the problem is (2, 0).

<u>Y - Intercept</u>
f(x) = -x² + 4x - 4
f(x) = -(0)² + 4(0) - 4
f(x) = -(0) + 0 - 4
f(x) = -0 + 0 - 4
f(x) = 0 - 4
f(x) = -4

The y - intercept of the problem is (0, -4).
<u />
8 0
3 years ago
Why does each number only have one square root?
Tamiku [17]

Answer:

it gets  multiplied by the value of the root .that is just more concise way of writing it .

Step-by-step explanation:

3 0
3 years ago
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