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2 years ago

10

A circular patio has a diameter of 12 feet. Holly is stringing lights around the edge of the patio. Approximately how many feet

of stringed lights does Holly need? Use 3. 14 for π. Enter your answer as a decimal in the box. Feet.

1 answer:

Bogdan [553]2 years ago

5 0

Answer:

2.15

Step-by-step explanation:

I worked out the problem use calculator yo double check

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Please please please please please help me!!!!!

Bond [772]

Answer:

c

Step-by-step explanation: just trust me.

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3 years ago

-20 • 3<br> ——————— =<br> -30 ÷ 3

luda_lava [24]

-20 * 3 / -30 / 3

First multiply the top and divide the bottom to simplify the problem:

-20 * 3 = -60

-30/3 = -10

Now you have -60 / -10

Divide:

-60 / -10 = 6

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3 years ago

Read 2 more answers

Write a polynomial of least degree in standard form that has real coefficient, a leading coefficient of 1 and zeros at 1,-2, and

mario62 [17]

Answer:3i

Step-by-step explanation:

8 0

3 years ago

The scatter plot shows the number of people visiting a walking track on 15 different days and the temperature on those days.

Maslowich

Answer: b

Step-by-step explanation: I think

3 0

3 years ago

A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly locat

DiKsa [7]

Answer:

The probability of a selection of 50 pages will contain no errors is 0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let $\mu$ be the random variable that follows a Poisson distribution, then mean $\mu = \dfrac{10}{500}= 0.02$

and the mean that the random selection of 50 pages will contain no error is $\lambda = 50 \times 0.02 =1$

∴

$Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}$

Pr(q =0) = 0.368

The probability of a selection of 50 pages will contain no errors is 0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2

$P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]$

$P(X \geq 2) = 1 - [0.3678 +0.3678]$

$P(X \geq 2) = 1 -0.7356$

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

6 0

3 years ago