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bearhunter [10]
2 years ago
13

Abigail starts work at 8:00 am and Zavier starts at 7:00 am. They both finish at the same time. If abigail works x hours, how ma

ny hours does Zavier work?​
Mathematics
2 answers:
Tamiku [17]2 years ago
7 0
X+1 Hours, because Zavier begins work an hour earlier than Abigail.
dedylja [7]2 years ago
6 0

Answer:

Zavier would work an extra hour but would get off at the same time as Abigail so your answer is X+1

Step-by-step explanation:

Since we know that Abigail starts her workday an hour after Zavier then they both get off at the same time that means Zavier works another hour before Abigail starts work.

Hope this helps :)

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           \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

       <em>Evaluate 1/4c+3d when c=6, and d=7.</em>

<em />

<em>         </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

       Replace c with 6, and d with 7:-

     \Large\text{$\displaystyle\frac{1}{4} (6)+3(7)$}

\bigstar On simplification,

   \Large\text{$\displaystyle\frac{1}{4} \times\frac{6}{1}+21$}

\bigstar On further simplification,

    \Large\text{$\displaystyle\frac{6}{4} +21$}

\bigstar On further simplification,

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\bigstar Adding the numerators,

\Large\text{$\displaystyle\frac{90}{4}$}

\bigstar Finally, Reducing the fraction:-

\Large\text{$\displaystyle\frac{45}{2}$}

\Uparrow \mathbb{OUR\:SIMPLIFIED\:EXPRESSION}

<h3>Good luck with your studies.</h3>

         \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}

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s(c) = 7c+50.
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3 years ago
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