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bearhunter [10]
2 years ago
13

Abigail starts work at 8:00 am and Zavier starts at 7:00 am. They both finish at the same time. If abigail works x hours, how ma

ny hours does Zavier work?​
Mathematics
2 answers:
Tamiku [17]2 years ago
7 0
X+1 Hours, because Zavier begins work an hour earlier than Abigail.
dedylja [7]2 years ago
6 0

Answer:

Zavier would work an extra hour but would get off at the same time as Abigail so your answer is X+1

Step-by-step explanation:

Since we know that Abigail starts her workday an hour after Zavier then they both get off at the same time that means Zavier works another hour before Abigail starts work.

Hope this helps :)

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Solve the system of 2x-5y+z=1 3 y+2z=5-24z=48
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3 years ago
Y=-1/2x+1 and y=1/3+6
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John is twice as old as his son. In 42 years, the ratio of their ages will be 4:3. What is the son's current age?
dsp73

Answer: Jhon is 42 years old, and his son is 21 years old.

Step-by-step explanation:

Let's define:

J = John's age

S = Age of the son.

We know that:

"John is twice as old as his son"

J = 2*S

"In 42 years, the ratio of their ages will be 4:3. What is the son's current age?"

In 42, their ages will be:

J + 42 and S + 42.

And the ratio 4:3 means that:

(J + 42) = (4/3)*(S + 42)

Then we have the system of equations:

J = 2*S

(J + 42) = (4/3)*(S + 42)

To solve it we can first replace the first equation into the second one, to get:

(2*S + 42) = (4/3)*(S + 42)

2*S  - (4/3)*S = (4/3)*42 - 42

S*(6/3 - 4/3) = (1/3)*42

S*(2/3) = (1/3)*42

S = (3/2)*(1/3)*42 = 21.

And we can find Jonh's age if we use the first equation:

J = 2*S = 2*21 = 42

Jhon is 42 years old, and his son is 21 years old.

8 0
3 years ago
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