Question

Find the value of the length x rounded to 1 DP.

Answer 1

Answer:

x = 13.6 cm

Step-by-step explanation:

part A:

using tan rule:

$tan(x) = \frac{opposite}{adjacent}$

$tan(39) = \frac{6}{adjacent}$

$adjacent = \frac{6}{tan(39)}$

$adjacent = 7.41$

part B:

using tan rule:

$tan(x) = \frac{opposite}{adjacent}$

$tan(44) = \frac{6}{adjacent}$

$adjacent = 6.213$

Total length of x:

part A + part B

$7.41 + 6.213$

$13.6$ cm

Answer 2

Answer:

x = 13.6 (1 dp)

Step-by-step explanation:

Using the following trig ratio to calculate the base of each triangle:

$tan(\theta)=\dfrac{O}{A}$

where $\theta$ is the angle, O is the side opposite the angle and A is the side adjacent to the angle.

Left triangle

Given:

• $\theta$ = 39
• O = 6
• A = $x_1$

$\implies tan(39) = \dfrac{6}{x_1}$

$\implies x_1 = \dfrac{6}{tan(39)}$

Right triangle

Given:

• $\theta$ = 44
• O = 6
• A = $x_2$

$\implies tan(44) = \dfrac{6}{x_2}$

$\implies x_2 = \dfrac{6}{tan(44)}$

Length of x

      $x = x_1+x_2$

$\implies x=\dfrac{6}{tan(39)}+\dfrac{6}{tan(44)}$

$\implies x=13.6$ (1 dp)