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lorasvet [3.4K]
3 years ago
5

How many times does 61 go into 340

Mathematics
2 answers:
Dmitry [639]3 years ago
8 0
Three times evenly but if you were to have an exact answer it is 5.57 times
TiliK225 [7]3 years ago
4 0
I think maybe about 5 times
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A bag contains Red, Green and Yellow balls. A ball is taken at random from the bag. The probability that it is Red is 0.35 and t
Eddi Din [679]

Answer:

  • P(Yellow)=0.25
  • P(Not Red)=0.65

Step-by-step explanation:

P(Red)=0.35

P(Green)=0.4

(a)Since there are three colours inside the bag

P(Red)+P(Green)+P(Yellow)=1

0.35+0.4+P(Yellow)=1

P(Yellow)=1-(0.35+0.4)

P(Yellow)=0.25

(b) In probability, the sum of an event and its complement is 1.

Therefore:

P(Red)+P(Not Red)=1

0.35+P(Not Red)=1

P(Not Red)=1-0.35

P(Not Red)=0.65

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3 years ago
Gail is 6 years younger than Mark.Let m= Mark’s age which expression equals Gail’s age?
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3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

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3 years ago
For f(x)-4x+1 and g(x)-x^2-5, find (g/f) (x)
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Answer:

A.

Step-by-step explanation:

let me know if you want an explanation :))

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